Why Are
|
Thread.stop
deprecated?
Because it is inherently unsafe. Stopping a thread causes it to unlock all
the monitors that it has locked. (The monitors are unlocked as the
ThreadDeath
exception propagates up the stack.) If any of the
objects previously protected by these monitors were in an inconsistent state,
other threads may now view these objects in an inconsistent state.
Such objects are said to be damaged.
When threads operate on damaged objects, arbitrary behavior can result.
This behavior may be subtle and difficult to detect, or it may be
pronounced. Unlike other unchecked exceptions,
ThreadDeath
kills threads silently; thus, the user has no
warning that his program may be corrupted. The corruption can manifest
itself at any time after the actual damage occurs, even hours or days in the
future.
ThreadDeath
exception and
fix the damaged object?In theory, perhaps, but it would vastly complicate the task of writing correct multithreaded code. The task would be nearly insurmountable for two reasons:
ThreadDeath
exception almost
anywhere. All synchronized methods and blocks would have to be studied
in great detail, with this in mind.
ThreadDeath
exception
while cleaning up from the first (in the catch
or
finally
clause). Cleanup would have to repeated till it
succeeded. The code to ensure this would be quite complex.
Thread.stop(Throwable)
?
In addition to all of the problems noted above, this method may be used to
generate exceptions that its target thread is unprepared to handle (including
checked exceptions that the thread could not possibly throw, were it not for
this method). For example, the following method is behaviorally identical to
Java's throw
operation, but circumvents the compiler's attempts
to guarantee that the calling method has declared all of the checked exceptions
that it may throw:
static void sneakyThrow(Throwable t) { Thread.currentThread().stop(t); }
Thread.stop
?
Most uses of stop
should be replaced by code that simply modifies
some variable to indicate that the target thread should stop running. The
target thread should check this variable regularly, and return from its run
method in an orderly fashion if the variable indicates that it is to stop
running.
(This is the approach that JavaSoft's Tutorial
has always recommended.)
To ensure prompt communication of the stop-request, the variable
must be volatile (or access to the variable must be synchronized).
For example, suppose your applet contains the following
start
, stop
and run
methods:
private Thread blinker; public void start() { blinker = new Thread(this); blinker.start(); } public void stop() { blinker.stop(); // UNSAFE! } public void run() { Thread thisThread = Thread.currentThread(); while (true) { try { thisThread.sleep(interval); } catch (InterruptedException e){ } repaint(); } }You can avoid the use of
Thread.stop
by replacing
the applet's stop
and run
methods with:
private volatile Thread blinker; public void stop() { blinker = null; } public void run() { Thread thisThread = Thread.currentThread(); while (blinker == thisThread) { try { thisThread.sleep(interval); } catch (InterruptedException e){ } repaint(); } }
That's what the Thread.interrupt
method is for. The same
"state based" signaling mechanism shown above can be used, but the
state change (blinker = null
, in the previous example)
can be followed by a call to Thread.interrupt
, to
interrupt the wait:
public void stop() { Thread moribund = waiter; waiter = null; moribund.interrupt(); }For this technique to work, it's critical that any method that catches an interrupt exception and is not prepared to deal with it immediately reasserts the exception. We say reasserts rather than rethrows, because it is not always possible to rethrow the exception. If the method that catches the
InterruptedException
is not
declared to throw this (checked) exception, then it should "reinterrupt
itself" with the following incantation:
Thread.currentThread().interrupt();This ensures that the Thread will reraise the
InterruptedException
as soon as it is able.
Thread.interrupt
?
In some cases, you can use application specific tricks. For example,
if a thread is waiting on a known socket, you can close the socket
to cause the thread to return immediately. Unfortunately, there
really isn't any technique that works in general. It should
be noted that in all situations where a waiting thread doesn't respond to
Thread.interrupt
, it wouldn't respond to
Thread.stop
either. Such cases include deliberate
denial-of-service attacks, and I/O operations for which thread.stop
and thread.interrupt do not work properly.
Thread.suspend
and Thread.resume
deprecated?
Thread.suspend
is inherently deadlock-prone. If the target
thread holds a lock on the monitor protecting a critical system resource when
it is suspended, no thread can access this resource until the target thread
is resumed. If the thread that would resume the target thread attempts to
lock this monitor prior to calling resume
, deadlock results.
Such deadlocks typically manifest themselves as "frozen" processes.
Thread.suspend
and
Thread.resume
?
As with Thread.stop
, the prudent approach is to have the
"target thread" poll a variable indicating the desired state of the
thread (active or suspended). When the desired state is suspended,
the thread waits using Object.wait
. When the thread is
resumed, the target thread is notified using Object.notify
.
For example, suppose your applet contains the following mousePressed event
handler, which toggles the state of a thread called blinker
:
private boolean threadSuspended; Public void mousePressed(MouseEvent e) { e.consume(); if (threadSuspended) blinker.resume(); else blinker.suspend(); // DEADLOCK-PRONE! threadSuspended = !threadSuspended; }You can avoid the use of
Thread.suspend
and
Thread.resume
by replacing the event handler above with:
public synchronized void mousePressed(MouseEvent e) { e.consume(); threadSuspended = !threadSuspended; if (!threadSuspended) notify(); }and adding the following code to the "run loop":
synchronized(this) { while (threadSuspended) wait(); }The
wait
method throws the InterruptedException
, so
it must be inside a try ... catch
clause. It's fine
to put it in the same clause as the sleep
. The check should
follow (rather than precede) the sleep
so the window is
immediately repainted when the the thread is "resumed." The resulting
run
method follows:
public void run() { while (true) { try { Thread.currentThread().sleep(interval); synchronized(this) { while (threadSuspended) wait(); } } catch (InterruptedException e){ } repaint(); } }Note that the
notify
in the mousePressed
method and
the wait
in the run
method are inside
synchronized
blocks. This is required by the language, and
ensures that wait
and notify
are properly
serialized. In practical terms, this eliminates race conditions that could
cause the "suspended" thread to miss a notify
and remain suspended
indefinitely.
While the cost of synchronization in Java is decreasing as the platform matures, it will never be free. A simple trick can be used to remove the synchronization that we've added to each iteration of the "run loop." The synchronized block that was added is replaced by a slightly more complex piece of code that enters a synchronized block only if the thread has actually been suspended:
if (threadSuspended) { synchronized(this) { while (threadSuspended) wait(); } }The resulting
run
method is:
public void run() { while (true) { try { Thread.currentThread().sleep(interval); if (threadSuspended) { synchronized(this) { while (threadSuspended) wait(); } } } catch (InterruptedException e){ } repaint(); } }In the absence of explicit synchronization, threadSuspended must be made volatile to ensure prompt communication of the suspend-request.
To rectify this situation, the stop method must ensure that the target thread resumes immediately if it is suspended. Once the target thread resumes, it must recognize immediately that it has been stopped, and exit gracefully. Here's how the resulting run and stop methods look:
public void run() { Thread thisThread = Thread.currentThread(); while (blinker == thisThread) { try { thisThread.sleep(interval); synchronized(this) { while (threadSuspended && blinker==thisThread) wait(); } } catch (InterruptedException e){ } repaint(); } } public synchronized void stop() { blinker = null; notify(); }If the stop method calls Thread.interrupt, as described above, it needn't call notify as well, but it still must be synchronized. This ensures that the target thread won't miss an interrupt due to a race condition.
Thread.destroy
?Thread.destroy
has never been implemented. If it were
implemented, it would be deadlock-prone in the manner of
Thread.suspend
. (In fact, it is roughly equivalent to
Thread.suspend
without the possibility of a subsequent
Thread.resume
.) We are not implementing it at this time,
but neither are we deprecating it (forestalling its implementation in
future). While it would certainly be deadlock prone, it has been argued
that there may be circumstances where a program is willing to risk
a deadlock rather than exit outright.
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